.0196=m^2

Solution for .0196=m^2 equation:

.0196=m^2

We move all terms to the left:

.0196-(m^2)=0

We add all the numbers together, and all the variables

-1m^2+0.0196=0

a = -1; b = 0; c = +0.0196;
Δ = b2-4ac
Δ = 02-4·(-1)·0.0196
Δ = 0.0784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0784}}{2*-1}=\frac{0-\sqrt{0.0784}}{-2}
=-\frac{\sqrt{}}{-2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0784}}{2*-1}=\frac{0+\sqrt{0.0784}}{-2}
=\frac{\sqrt{}}{-2}
$